The area of a rectangle is 35ft^2 , and the length of the rectangle is 3 ft more than twice the width. Find the dimensions of the rectangle.

Answer 1

A= LW = 35 = (W+3)W = W^2 + 3W

W^2 + 3W -35 = 0

(W+3W + 9/4) = 35 + 9/4 = 149/4

(W+ 3/2)^2 = 149/4

W + 3/2 = + or - (1/2)sqr149

W= -3/2 + (1/2)sqr149 = about -1.5 + 6.1 = about 4.6

L= about 4.6 + 3 = 7.6

4.6(7.6) = 35 rounded off to nearest integer