
Niki D.
asked 06/28/21Determine the area common to r= 3+3sintheta and r=3
Please help.
The instruction says the answer must be in Exact form.
Determine the area common to r= 3 + 3sintheta and r= 3
when I graphed this it is a cardioid and a circle, I am having hard time starting to solve for this because when i try to fin the intersection using r1+r2 it givesss weird results
our topic right now is about polar curves and polar regions.
thank you so much
2 Answers By Expert Tutors

Bradford T. answered 06/29/21
Retired Engineer / Upper level math instructor
If you plot the polar graph of the two functions and observe what is "in common" between the two curves. The top part is a semicircle, A= πr2/2 and the bottom part is the double humps. So the hard part is to find the area of the double hump portion below the x-axis. This portion of 3+3sinθ goes from θ=π to 2π.
So the area of the bottom part is (1/2)∫r2(θ)dθ integrated from π to 2π.
Then add that value to the semicircle area.

Andre W. answered 06/29/21
Math Class Domination! with Andre!!
The best way to look at this problem is by graphing it on a spiral graph with these given polar coordinates r and theta. For the first graph is not involved in the sin part of the function because b is the exponent in front of the sin(theta) and b= 0 in this r = 3 spiral graph!!
r = radius and all you need is angle which in this case is in radians (portion of pi)
Also it is good to just find the intersection points of the 2 functions
set equations equal to each other to find the r, then plug it into one of the original equations to find theta and now you have the 2 intersection points on these 2D polar functions!!
They intersect at points (3, 0) and (-3, pi) where 0 in the first point is in radians like the 2nd y coordinate pi is in radians (which is 180 degrees converted to radians)
Think Trig, not degrees !! I mean Unit Circle as a corresponding situation with sin and radians in terms of pi!!
And the area between will have a "range" of (0,3) (for y values if it is an x,y graph) and in the vertical (pi/2) direction a "domain" of (-3,3) (for x values if it is a x,y graph)
And of course it will still keep that cardoid shape on the bottom "humps" !!
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Mark M.
Did you draw the gtwo equations?06/29/21