Raymond B. answered 06/28/21
Math, microeconomics or criminal justice
d=rt distance = rate of speed times time traveled
d = (b+c)t = (b-c)(t+24)
b= boat speed in still water, c= current speed, t= time going down stream
(b+4)t = (b-4)(t+24) = 60
t= 60/(b+4)
(b-4)(60/(b+4) + 24) = 60 multiply both sides by b+4
b^2 = 36
b = 6 mph = boat speed in still water
10mph down stream, 2 mph upstream
10(6)= 60 = 2(30)
4599 = d = distance
w=5 mph = wind speed
t against wind = t+10, t= time with the wind
p= speed of the plane with no wind = 68 mph
(p+w)t = 4599
(p+5)t = 4599 = (p-5)(t+10)
t = 4599/(p+5)
(p-5)(499/(p+5) +10) = 4599
multiply both sides by p+5
4599p - 22995 +10p^2 -250 = 4599p + 22995
10p^2 = 46240
p = 68 mph
p^2 = 424
p = sqr424 = about 20.6 mph= planes speed with no wind