FIND THE DISTANCE

Question

A particle moves in a straight line and its position is given by s(t) = t ³ - 6t² - 15t + 40, where ''s'' is measured in feet and ''t'' in seconds.

Find the total distance traveled in the first 10 seconds

to. 390 feet

b. 350 feet

c. 290 feet

d. 450 feet

e. 600 feet

Answer 1

290

just plug 10 for t and simplify

s=t^3 -6t^2 -15t + 40

s = 10^3 - 6(10^2) -15(10) + 40 = 290

Answer 2

Since the distance equation is given as s(t) = t ³ - 6t² - 15t + 40, then you can use the equation to compute the distance travelled in the first 10 seconds by substituting t = 10 sec into the equation

S(10) =(10)³ -6(10)² -15(10) +40 = 290 ft

Answer is C