Raymond B. answered 06/21/21
Math, microeconomics or criminal justice
6 = ab^0 + c = a + c
42 = ab^1 +c = ab+c
6=a + c, c = 6-a
42 = ab + c = ab+ 6-a = (b-1)a + 6
(b-1)a = 42-6 = 36
let a = 1, then
b-1 = 36
b= 37 and c=6-1 = 5
f(x) = 37^x + 5
f(0) = 37^0 + 5 = 1+5 = 6
f(1) = 37^1 + 5 = 37+5 = 42
f(x) = 37^x + 5 is one solution among an infinite number of exponential functions