
Yefim S. answered 06/17/21
Math Tutor with Experience
Let f(x) = x3; Δf = f(2.99) - f(3); f(2.99) = f(3) + Δf ≈ 33 + df = 27 + f'(3)·Δx = 27 + 3·32(2.99 - 3) = 27 - 0.27 =
26.73
With calculator: 2.993 = 26.7309
Tom B.
asked 06/17/21Use differentials to approximate the value of the expression. Compare your answer with that of a calculator. (Round your answers to four decimal places.)
(2.99)^3
Using differentials _____________________
Using calculator _______________________
Yefim S. answered 06/17/21
Math Tutor with Experience
Let f(x) = x3; Δf = f(2.99) - f(3); f(2.99) = f(3) + Δf ≈ 33 + df = 27 + f'(3)·Δx = 27 + 3·32(2.99 - 3) = 27 - 0.27 =
26.73
With calculator: 2.993 = 26.7309
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