Write an equation for a line perpendicular to 3y + 9 x = - 6 and passing through the point (6,3)

Question

Write an equation for a line perpendicular to 3y + 9 x = - 6 and passing through the point (6,3)

Answer 1

3y+9x =-6

solve for y

3y = -9x-6 divide by 3

y = -3x -2 the coefficient of the x term is the slope. For a perpendicular line change the sign and flip it upside down to get +1/3 = slope of the perpendicular line

y= (1/3)x + b. To solve for b, plug in the point (6,3)

3 = (1/3)(6) + b

b = 3-2 = 1

y = (1/3)(x) + 1

is the equation of the perpendicular through the point (6,3)

or multiply by 3 to get

3x = x +3