What is the equation of the line that passes through the point (−5,−2) and has a slope of −6/5

Answer 1

y = -6x/5 + b plug in the point (-5,-2) to solve for b

-2 = -(6)(-5)/5 + b

b = -2 -6 = - 8

y =-6x/5 - 8 is the line with slope -6/5 through the point (-5,-2)

or you could start with a slope = slope type equation, in point slope form

(y+2)/(x+5) = -6/5 multiply both sides by x+5

y+2 = -6x/5 - 6 subtract 2 from both sides

y = -6x/5 - 8

if you want multiply by 5 to get

5y =-6x - 40

6x + 5y = -40