Need some help with these.

Question

Answer 1

the larger the absolute value of the coefficient of the x^2 term, the more narrow the parabola

widest to narrowest:

8 y = -2x^2, y= 4x^2, y=-6x^2 l-2l<l4l<l-6l

9 y= (1/3)x^2, y=x^2, y=2x^2 l1/3l < l1l < l2l

10 y = (1/6)x^2, y=(1/4)x^2, y=(1/2)x^2 1/6<1/4<1/2

upward opening parabolas: 11, 12, 13 and 16, because the coefficient of the x^2 term is>0

downward opening parabolas 14 and 15 because the coefficient of the x^2 term is <0

y intercepts are the constant terms

11 1

12 -2

13 1

14 5

15 -4

16 -10

axis of symmetry: all have x=0

vertices:

11 (0,1)

12 (0,-2)

13 (0,1)

14 (0,5)

15 (0,-4)

16 (0,-10)

no x intercepts: 11, 13 and 15

x intercepts: 12 and 16: + and - sqr2,

14: + and - sqr10