Find an equation for the line parallel to 3y + 27x = 15

Question

Find an equation for the line parallel to 3y+27x=15 and goes through the point (-6,7). Write your answer in the form y=mx+b

Y=?

Answer 1

Equation : 3y + 27x = 15

3y = 15 - 27x

y = 5 - 9x

∴ slop = -9 parallel lines have same slope

∴ y = -9x + b line goes through ( -6 , 7 )

7 = -9 × -6 + b

7 - 54 = b

b = -47

Equation of parallel line y = -9x - 47

Answer 2

The slope of the given line is -9...find it by putting the equation in slope-intercept form.

The -9= (y-7)/(x+6)...which you can put into slope-intercept form