Convert (-3, 2π) to a rectangular coordinate

Question

Convert (-3, 2π) to a rectangular coordinate

Answer 1

(r, theta) = (-3, 2pi)

(x,y) = (rcos(theta), rsin(theta) = (-3(cos2pi), -3sin(2pi)) = (-3(1), -3(0)) = (-3,0)

Answer 2

x = -3cos2π = - 3; y = - 3sin2π = 0

(- 3, 2π) = (-3, 0)