Raymond B. answered • 05/25/21
Tutor
5
(2)
Math, microeconomics or criminal justice
(27y)^2/3 falsely = cube root of 27y^2 = 3y^2/3
the error is treating (27y)^2/3 as if it were 27(y^2/3)
(27y)^2/3 = the cube root of (27^2y^2) = 9y^2/3 NOT 3y^2/3
cube root of 27^2 is cube root of 729 = 9. 9x9x9 = 729.
0 110 220 330
260 130 65 32.5
is a geometric sequence
a1 =260
a2 = 130
a3 = 65
a4 =32.5
an = 260(1/2)^(n-1)
f(x) =n=x/110 + 1= n
f(110) = 1+1=2= n
f(220) = 2+1 = 3 = n
f(n) = an
an = a1r^(n-1) for a1 = 18 and r= 1/2
an = 18(1/2)^(n-1)
for the table f(x) =an = 8(2)^(n-1)
a1 = 8
a2 =8(2) = 16
a3 =8(2^2) = 32
a4 = 8(2^3) = 64
