The first side of a triangle is 8m longer than twice the second side. The third side is three times the second side. The perimeter is 128m. Find the lengths of the three sides.

Answer 1

F= 8+2S

T=3S

F+S+T = 128

8+2S + S + 3S = 128

6S = 128-8 = 120

S = 120/6 = 20 m = second side

T=60 m = third side

F=48 m = first side