A line includes the points (6,5) and (10,3). What is its equation in point-slope form?

Answer 1

(6,5),(10,3) are points on a line with slope = (3-5)/(10-6) = -2/4= -1/2

y=(-1/2)x + b, solve for b by plugging in either point

3=(-1/2)10 + b

b = 3+5 = 8

the line is

y=-x/2 + 8 in slope intercept form. the intercept is a point on the line (0,8)

or

(y-5)/(x-6) = -1/2

y-5 = (-1/2)(x-6)

using point (6,5) and slope =-1/2

or use the other point

(y-3)/(x-10) = -1/2

y-3 = (-1/2)(x-10)