x ^ 2 = 6x - 8, state the vertex and identify it as a maximum or minimum.

Answer 1

x^2-6x+8 =

x^2 -6x + 9 = -8 +9 = 1

(x-3)^2 -1 = 0

vertex = (3,-1)

general form of the quadratic in vertex form is (x-h)^2 + k where (h,k) is the vertex. In this example h=3 and k=-1. In this problem the vertex is a minimum. the graph is an upward opening parabola, with the vertex as the minimum point.

the vertex is a minimum when the coefficient of the x^2 term is positive