Raymond B. answered 05/20/21
Tutor
5
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Math, microeconomics or criminal justice
6x^2-x-2 = (3x-2)(2x+1) zeros are 2/3 and -1/2
x^2-x-2 = (x-2)(x+1) zeros are 2 and -1 or 2/1 and -1/1
in fractional form both polynomials have zeros with the same numerators