Anthony T. answered • 05/13/21

Patient Math & Science Tutor

log_{4}(2x+1)+1=log_{4}(x+5)

1 = log_{4} 4

log_{4} (2X +1) + log_{4} 4 = log_{4}(X+5) sum of logs = log of products

log_{4} (4 * (2X+1)) = log_{4}(X+5) take antilogs (if the logs of two expressions are equal, the expressions must be equal)

4 * (2X+1) = (X+5) Solve for X

X = 1/7

Miranda G.

Thank you!!!!!!05/14/21