what two digets have a sum of 16 and a difference of 2??

Question

PLEASE TELL ME ANSWER!!!

Answer 1

I won't tell you the answer, but I will tell you how to find it.

Let x and y be the two unknown numbers, They have a sum of 16 so x + y = 16. They have a difference of 2, so x - y = 2. Now you have two equations:

x + y = 16

x - y = 2

Let's add a y to both sides of the second equation:

x - y = 2

x - y + y = 2 + y

x = 2 + y

Now substitute 2 + y in place of x in the first equation:

x + y = 16

2 + y + y = 16

2 + 2y = 16

Solve for y. Once you have the value of y, x = 2 + y.

Answer 2

Hi Evelynn G

You know you have two digits, x and y that add to 16 and subtract to 2. One could also consider what is not given about the digits;the information does not describe consecutive digits. We are only given

x + y = 16

The information does indicate that for a given digit fx the other digit y is x - 2 because

x - y = 2

If you solve x - y = 2 for y

You start by

Subtracting x from both sides of the equation to give

-y = - x + 2

Divide both sides by negative 1

y = x - 2

You can use the information to put everything in terms of x by making the appropriate substitution

x + x - 2 = 16

Can you continue from here?