Tamara J. answered 03/14/13
Math Tutoring - Algebra and Calculus (all levels)
The equation will be in slope-intercept form: y = mx + b ,
where m is the slope of the line and b is the y-intercept.
We are given that the line in question has a y-intercept of 1, which means that b = 1.
We are also told that the line in question has to be parallel to the line -3x - 2y = -9. Since parallel lines have the same slope, we need to find the slope of this line by rearranging it into slope-intercept form (y=mx+b). The slope of the line in question will be the same as the slope of this line.
-3x - 2y = -9 add 3x to both sides of the equation
-2y = 3x - 9 divide both sides of the equation by -2
y = (3x - 9)/-2
= 3x/(-2) - 9/(-2)
y = (-3/2)x + (9/2)
The equation of the line indicates that the line has a slope of -3/2; that is, m = -3/2.
We can now determine the equation of the line in question:
y = mx + b , m = -3/2 and b = 1
y = (-3/2)x + 1