Find an equation of the line that (a) has y-intercept of 1 and (b) is parallel to the line -3 x -2 y = -9.

Write your answer in the form y=mx+b.

Find an equation of the line that (a) has y-intercept of 1 and (b) is parallel to the line -3 x -2 y = -9.

Write your answer in the form y=mx+b.

Tutors, please sign in to answer this question.

The equation will be in slope-intercept form: y = mx + b ,

where m is the slope of the line and b is the y-intercept.

We are given that the line in question has a y-intercept of 1, which means that **b = 1**.

We are also told that the line in question has to be parallel to the line -3x - 2y = -9. Since parallel lines have the same slope, we need to find the slope of this line by rearranging it into slope-intercept form (y=mx+b). The slope of the line in question will be the same as the slope of this line.

-3x - 2y = -9 add 3x to both sides of the equation

-2y = 3x - 9 divide both sides of the equation by -2

y = (3x - 9)/-2

= 3x/(-2) - 9/(-2)

y = **(-3/2)**x + (9/2)

The equation of the line indicates that the line has a slope of -3/2; that is, **m = -3/2**.

We can now determine the equation of the line in question:

y = mx + b , m = -3/2 and b = 1

** y = (-3/2)x + 1**

_{1}=m(x-x_{1}). y_{1} is the y-intercept, so plug in 1 for y_{1} and your slope is -3/2, so plug that in for m. Nothing was specified for x_{1} so you can just enter 0. Thus, your equation now looks like y-1=(-3/2)(x-0). Solve this equation so that it is in the form of y=mx+b. Your final answer will be y=(-3/2)x+1.

Kasey H.

Chemistry/Math/Art History Tutor: Elementary - College Level

New York, NY

4.8
(5 ratings)

Dani V.

Patient and Experienced ACT, SAT, SSAT, and ISEE Tutor

New York, NY

4.9
(173 ratings)

Ryan S.

Ivy League Tutor, SAT and Regents Pro!

New York, NY

4.8
(17 ratings)