HELP IS NEEDED !!!!

Question

Write the equation, in vertex form, for the quadratic function whose vertex is (3, –1) and goes through point (–1, 7).

Answer 1

y=a(x-3)^2 -1

7=16a -1

16a = 8

a =1/2

y = (1/2)(x-3)^2 -1

or

2y = (x-3)^2 -2

or

f(x) = (1/2)(x^2 -6x +9) -1

f(x) = x^2/2 -3x +7/2