A tennis player hits a ball 3 feet above the ground with a velocity of 60 ft/sec. After how many seconds will the ball hit the ground?

Question

If an object has been thrown or launched, the formula to model the height of the object t seconds after it has been launched is: Remember V is velocity and h is the starting point /height.

h(t) = -16t2 + v0t + h0.

Answer 1

h(t) = -16t^2 + 60t + 3

set equal to zero, for ground zero

then

-16t^2 +60t +3 = 0 multiply by -1

16t^2 - 60t - 3 = 0, use the quadratic formula

t = 60/32 + (1/32)sqr(60^2+64(3))

= about (60+19.3)/32 = about 2.5 seconds to hit the ground