A tennis player hits a ball 3 feet above the ground with a velocity of 60 ft/sec. After how many seconds will the ball be at a height of 3 feet again?

Question

If an object has been thrown or launched, the formula to model the height of the object t seconds after it has been launched is: Remember V is velocity and h is the starting point /height.

h(t) = -16t2 + v0t + h0.

Answer 1

-16t^2 + 60t + 3 =3

t(-16t +60) = 0

t = 0 and t=60/16 = 15/4 = 3 3/4 seconds