
Yefim S. answered 05/06/21
Math Tutor with Experience
Total possible outcomes is C(6, 3). Positive outcames C(3, 2),
So, Pr(X = 2) = C(3,2)/C(6,3) = [3!/(2!1!)]/[6!/(3!3!)] = 3/20
Ma F.
asked 05/05/21There are 4 women and 2 men waiting on standby for a flight to New York. Suppose that 3 of these 6 people are chosen at random for the flight. If the random variable 𝑋 counts the number of women chosen. Find Pr [𝑋=2] .
Yefim S. answered 05/06/21
Math Tutor with Experience
Total possible outcomes is C(6, 3). Positive outcames C(3, 2),
So, Pr(X = 2) = C(3,2)/C(6,3) = [3!/(2!1!)]/[6!/(3!3!)] = 3/20
This is a classic hypergeometric question.
The answer is 4C2 * 2C1 / 6C3 = .8
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.