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Question

In a classroom, there are 100 plastic fish in a tub. The tub is hidden from the students’ view. Some fish are green and some are yellow. The students know that there are 100 fish, but they don’t know how many of each color there are. The students go fishing, each time picking a random fish from the tub, recording its color, and throwing the fish back in the tub. At the end of the day, 65 fish have been chosen, 12 green and 53 yellow. What is the best estimate you can give for the number of green fish and the number of yellow fish in the tub? Describe how to calculate this best esti-mate, and explain why your method of calcula-tion makes sense in a way that a seventh-grader might understand. Is your best estimate neces-sarily accurate? Why or why not?

Answer 1

Out of 65 fish chosen, 12 are green.

65 fish - 12 green

1 fish - 12/65 green (divide both numbers by 65)

100 fish - (100 x 12/65) = 18.5 green

In the same way yellow fish 100 x (53/65) = 81.5

Obviously you can't have half a fish so these need to be whole numbers (integers)

So green - 19 and yellow - 81 or green 18 and yellow 82 are both possible solutions.

[ you have to make a decision about the green or the yellow then the other one is automatic as must add to 100 ]

So

So