Tom K. answered 04/23/21
Knowledgeable and Friendly Math and Statistics Tutor
There are 8 places the 3 empty hangers could be: 1-3, 2-4, 3-5, ..., 8-10
There are C(10,3) places where we could have the empty hangers.
Thus, the probability that the empty hangers are together is
8/C(10,3) = 8/120 = 1/15