There are 8 places the 3 empty hangers could be: 1-3, 2-4, 3-5, ..., 8-10
There are C(10,3) places where we could have the empty hangers.
Thus, the probability that the empty hangers are together is
8/C(10,3) = 8/120 = 1/15
Anand T.
asked 04/23/21Your cupboard has 10 hangers arranged in a row to hang clothes. There are 7 clothes hung.
Assume you picked hangers at random among the spaces available. Find the probability that
the three empty hangers are adjacent to each other.
There are 8 places the 3 empty hangers could be: 1-3, 2-4, 3-5, ..., 8-10
There are C(10,3) places where we could have the empty hangers.
Thus, the probability that the empty hangers are together is
8/C(10,3) = 8/120 = 1/15
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