Raymond B. answered 04/23/21
Math, microeconomics or criminal justice
zeros of a, b and c
y= j(x-a)(x-b)(x-c) = 0 then passing through a point (d,e)
e=j(d-a)(d-b)(d-c)
j= e/[(d-a)(d-b)(d-c)
(d-a)(d-b)(d-c)y = e(x-a)(x-b)(x-c) is a 3rd degree function with zeros a,b and c, passing through the point (d,e), with no fractions, or you could keep the fraction j and reduce it to lowest terms if you knew a,b,c,d, and e