Write a quadratic equation that passes through a vertex of (−3,2) and the point (−1,−10)

Question

please hep me with this math problem

Answer 1

y= a(x+3)^2 +2 solve for a by plugging in the other point

-10 = a(-1+3)^2 +2

-10 =16a +2

16a =-12

a =-12/16 = -3/4

y= f(x) = (-3/4)(x+3)^2 +2

if you want, eliminate the fraction to get

4y =-3(x+3)^ + 8