-5, 0 and 2
(x+5)x(x-2)
x^3 +3x^2 -10x
just take each zero and change their sign, then stick an x in front of it. that gives you the 3 factors. then multiply them together to get the polynomial which has those zeros
x^3+3x^2 -10x = 0 has 3 solutions, x=0, x=2 and x=-5
2^3 + 3(2^2) - 10(2) = 0
8 + 12 - 20 = 0
(-5)^3 + 3(-5)^2 - 10(-5) = 0
-125 + 75 + 50 = 0
(0)^3 + 3(0^2) -10(0) = 0
IF you graph f(x) = x^3 +3x^2 -10x the curve intersects the x axis 3 times, at (0,0), (2,0) and (-5,0)
