ln y = (x+6) ln x
(1/y)(dy/dx) = [(x+6)/x] + ln x
dy/dx = xx+6{[x+6)/x]+ln x}
Ezra H.
asked 04/16/21Please help I am very confused
Use logarithmic differentiation to find the derivative of the function.
y = xx + 6
y ' =
ln y = (x+6) ln x
(1/y)(dy/dx) = [(x+6)/x] + ln x
dy/dx = xx+6{[x+6)/x]+ln x}
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