logx2.5 = logx(5/2) = logx5 - logx2 = q - logx2 = p
So, logx2 = q - p
Using the change of base formula (converting from base 2 to base x), we have:
log25 = (logx5) / (logx2) = q / (q - p)
For part a, the answer is given???
Rosselyn U.
asked 04/11/21If logx2.5=p and logx5=q, find expressions in the terms of p and q for
a) logx2.5
b) log25
Thank you so much for your help!!
logx2.5 = logx(5/2) = logx5 - logx2 = q - logx2 = p
So, logx2 = q - p
Using the change of base formula (converting from base 2 to base x), we have:
log25 = (logx5) / (logx2) = q / (q - p)
For part a, the answer is given???
This is the most fundamental aspect of logarithms which you need to understand ; that is the ability to go from log to exponential form and visa versa
logx 2.5 = p is tasking what power do you need to raise x to to get 2.5. Well that by definition of logs is p
so this is equivalent to x^p= 2.5
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