Write an equation of the line that passes through the given point and is perpendicular to the graph of the given equation.

Question

(2,7); y=1/2x-11

(4,-5); 2x+2y=6

Answer 1

y=-2x + b (negative inverse of 1/2 is the slope of the perpendicular line; slope is

the coefficient of the x term when the equation is solved for x)

7=-2(2) + b

b = 7+4 = 11

y =-2x +11 is the equation of the perpendicular line through (2,7)

2x+2y = 6 divide by 2

x +y = 3 solve for y

y =-x +3, slope is -1, negative inverse = +1

y=x+b, plug in (4,-5) to solve for b

-5 = 4+b

b =-5-4= -9

y=x-9 is the perpendicular line through (4,-5)