Write this as a function ASAP

Question

Write the √16-x² / x as a function of theta where 0<theta< π, by making the substitution x=4sintheta.

16-x² are square rooted and over x

Answer 1

x = 4sinθ

√(16 - x²) / x = √(16 - 16sin²θ) / (4sinθ) = √[16(1 - sin²θ)] / (4sinθ) = 4√cos²θ / (4sinθ) = cosθ/sinθ = cotθ