when twice a positive whole number is added to its square,the result is 48.what is the number?

Answer 1

2x + x^2 = 48

x^2 + 2x - 48 = 0

(x+8)(x-6) = 0

x =-8 x=6

x=6 is the positive whole number

(unless by chance you might have meant 2x+(2x)^2 = 48

then 4x^2 + 2x -48, 2x^2 +x -24 = 0

then x=-1/4 + or - (1/4)sqr(1+96)

but then there is no positive whole number solution so go with x=6)