calculus helppp

Question

Consider the planes given by the equations

2𝑥+2𝑦−4𝑧=2,2x+2y−4z=2,

3𝑥+2𝑦+𝑧=6.3x+2y+z=6.

(a) Find a vector 𝑣⃗v→ parallel to the line of intersection of the planes. 𝑣⃗?

Find the equation of a plane through the origin which is perpendicular to the line of intersection of these two planes. 

This plane is 

Answer 1

Plane 1 = 2x+2y-4z=2 ... N1=2i+2j-4k

Plane 2 = 3x+2y+z=6 ... N2=3i+2j+k

N1XN2 yields a vector parall to the intersection of the two planes and is 10i-14j-2k that yields a plane 10x-14y-z= D that contains P(0,0,0) thus D=0.