Assuming the tangent at point 2014 would be parallel to the secant passingthrough the points 2012 and 2016,
the slope is rise/run = (25085 - 18066)/(2016 - 2012)
Sofia B.
asked 04/03/21The number N of locations of a popular coffeehouse chain is given in the table. (The numbers of locations as of October 1 are given.)
| Year | |
| 2008 | 16,680 |
| 2010 | 16,858 |
| 2012 | 18,066 |
| 2014 | 21,366 |
| 2016 | 25,085 |
Estimate the instantaneous rate of growth (in locations/year) in 2014 by measuring the slope of a tangent. (Round your answer to the nearest integer.)
Thank you.
Assuming the tangent at point 2014 would be parallel to the secant passingthrough the points 2012 and 2016,
the slope is rise/run = (25085 - 18066)/(2016 - 2012)
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