Net rate of change (in gallons/min) = V'(t) = E(t) - L(t)
a) V(2) = 38 + ∫02 (E(t) - L(t))dt
b) V'(2) = E(2) - L(2) (in gallons/min)
Audrey O.
asked 03/28/21How would you solve for a) & b) with a calculator?
I have a TI-89 Titanium.
At time t=0, a tank contains 38 gallons of water. Beginning at t=0, water flows into the tank at a rate of
E(t) = 12tsin(π/4t) gallons per minute, and water leaks out of the tank at a rate of L(t) = 6t2/ (t+2) gallons per minute.
a) How many gallons of water are in the tank at time t = 2 minutes?
b) What is the rate of change in the volume of water in the tank at t = 2 minutes? (Include appropriate units)
Net rate of change (in gallons/min) = V'(t) = E(t) - L(t)
a) V(2) = 38 + ∫02 (E(t) - L(t))dt
b) V'(2) = E(2) - L(2) (in gallons/min)
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