Write an equation of the line perpendicular to 2x - 3y + 1 = 0 and passing through the point (2, -1).

Question

Please show all your work! I need it as soon as possible!

Answer 1

2x- 3y +1 = 0

3y= 2x+1

y = (2/3)x + 1/3

slope of the perpendicular line is the negative inverse, of 2/3 = -3/2. change the sign and flip the fraction upside down, switch numerator and denominator

y=-(3/2)x + b. b=y intercept. to solve for b, plug in the point (2,-1)

-1 = (-3/2)(2) + b

b =-1 +3 = 2

y= -3x/2 + 2 is the perpendicular line through the point (2,-1)