Find two points on the graph of the parabola other than the vertex and x-intercepts

Question

t(x)=(x-4)^(2)+7

Vertex (4,7)

x intercept NoNe

Answer 1

(0,23) and (8,23)

t = (x-4)^2 + 7 = x^2-8x +16 + 7 = x^2-8x +23

t = x^2 -8x +23

23 is the t intercept or the point (0,23)

the parabola is symmetry around x =4, so (8,23) is another point on the parabola