
Kelsie S. answered 03/28/21
Experienced Tutor with an excellent background in mathematics.
Lily,
First we must find an equation to model the cost, the best way we can do this is to look at the areas of each part of the cylinder.
Let h = height of the cylinder
let r = radius of the cylinder
Surface area of the top/bottom: A = πr2
Surface area of the sides: A = 2πrh
So, let the cost be C
C = 2πrh(0.04) + πr2(0.04) + πr2(0.06)
This is restrained by the Volume: V = πr2h = 500cm3 ⇒ h = 500/πr2
Substitute this value for h into our cost equation to get:
C = πr[0.08(500/πr2) + 0.1r]
C = πr(40/πr2 + 0.1r)
C = 40/r + 0.1πr2
⇒ C' = -40/r + 0.1πr2
Set C' = 0 and solve for r.
C' = -40/r + 0.1πr2 = 0
⇒ r3 = 40/0.2π, so r ≈ 1.85 cm
h = 500/πr2 so, h≈ 46.33 cm
∴ C = π(1.85)[0.08(46.33) + 0.1(1.85)] = 22.62 cents
To ensure we have a minimum we must find C"
C" = 80/r3 + 0.2π > 0 for all r >0, so our solution is indeed a minimum.
I hope this helps and if you need any clarification where work hasn't been shown, please feel free to ask!