Inactive Tutor answered 03/28/21
Lily,
First we must find an equation to model the cost, the best way we can do this is to look at the areas of each part of the cylinder.
Let h = height of the cylinder
let r = radius of the cylinder
Surface area of the top/bottom: A = πr2
Surface area of the sides: A = 2πrh
So, let the cost be C
C = 2πrh(0.04) + πr2(0.04) + πr2(0.06)
This is restrained by the Volume: V = πr2h = 500cm3 ⇒ h = 500/πr2
Substitute this value for h into our cost equation to get:
C = πr[0.08(500/πr2) + 0.1r]
C = πr(40/πr2 + 0.1r)
C = 40/r + 0.1πr2
⇒ C' = -40/r + 0.1πr2
Set C' = 0 and solve for r.
C' = -40/r + 0.1πr2 = 0
⇒ r3 = 40/0.2π, so r ≈ 1.85 cm
h = 500/πr2 so, h≈ 46.33 cm
∴ C = π(1.85)[0.08(46.33) + 0.1(1.85)] = 22.62 cents
To ensure we have a minimum we must find C"
C" = 80/r3 + 0.2π > 0 for all r >0, so our solution is indeed a minimum.
I hope this helps and if you need any clarification where work hasn't been shown, please feel free to ask!