SLOPE INTERCEPT FORM equation for the line that goes through the point (-6,4) and is perpendicular to the line 2x-3y=3.

Question

How to slope Intercept form equation for the line that goes through the point (-6,4)

and its perpendicular to the line 2x-3y=3.?

Answer 1

2x - 3y = 3 solve for y, then the coefficient of the x term = slope

3y = 2x -3

y = 2x/3 -1, slope = 2/3 perpendicular line has slope = negative inverse = -3/2

y =-3x/2 + b. plug in the point to solve for b

-6 = -3(4)/2 + b

b = -6+6 = 0

y = -3x/2 is the perpendicular line through the given point