
Yefim S. answered 03/21/21
Math Tutor with Experience
(A) Velocity v'(x) = 182 - 28x;
(B) v(0) = 182 ft/s; v(2) = 182 - 28·2 = 126 ft/s
(C) v(x) = 0; 182 - 28x = 0; x = 182/28 = 6.5 s
Sean M.
asked 03/21/21If an object moves along the y-axis (marked in feet) so that its position at time x (in seconds) is given by f(x)=182x−14x2, find the following.
(A) The instantaneous velocity function v=f′(x)
(B) The velocity when x=0 and x=2 sec
(C) The time(s) when v=0
Yefim S. answered 03/21/21
Math Tutor with Experience
(A) Velocity v'(x) = 182 - 28x;
(B) v(0) = 182 ft/s; v(2) = 182 - 28·2 = 126 ft/s
(C) v(x) = 0; 182 - 28x = 0; x = 182/28 = 6.5 s
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