Find the equation of the line tangent to the graph of f at the indicated value of x. f(x)= 10e^x+2x​; x=0

Question

Find the equation of the line tangent to the graph of f at the indicated value of x.

f(x)= 10e^x+2x​; x=0

y= _________

Answer 1

I will leave it to you to figure f'(x).

f(0)= 1

f'(0)=12

Therefore, the equation of the tangent line is 12=(y-1)/x