I will leave it to you to figure f'(x).
f(0)= 1
f'(0)=12
Therefore, the equation of the tangent line is 12=(y-1)/x
Sean M.
asked 03/19/21Find the equation of the line tangent to the graph of f at the indicated value of x.
f(x)= 10e^x+2x; x=0
y= _________
I will leave it to you to figure f'(x).
f(0)= 1
f'(0)=12
Therefore, the equation of the tangent line is 12=(y-1)/x
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