Lower boundary z score is -2
x = lower z-score boundary for mean = 97 and standard deviation 16
z = (x - mean)/standard deviation
-2 = (x - 97)/16
x = 16(-2) + 97 = 65
upper boundary would be
x = 16(2) + 97 = 129
Jerry N.
asked 03/18/21IQ scores are measured with a test designed so that the mean is 97 and the standard deviation is 16. Consider the group of IQ scores that are unusual. What are the z scores that separate the unusual IQ scores from those that are usual? What are the IQ scores that separate the unusual IQ scores from those that are usual? (Consider a value to be unusual if its z score is less than −2 or greater than 2.)
What are the z scores that separate the unusual IQ scores from those that are usual?
The lower z score boundary is __________ (Simplify your answer.)
Lower boundary z score is -2
x = lower z-score boundary for mean = 97 and standard deviation 16
z = (x - mean)/standard deviation
-2 = (x - 97)/16
x = 16(-2) + 97 = 65
upper boundary would be
x = 16(2) + 97 = 129
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