determine the equation of a quadratic relation given the parabola has a maximum value of 10, an axis symmetry of x=-6, and a y -intercept of -3

Answer 1

max= vertex = (-6,10) a downward opening parabola

axis of symmetry x=-6, maximum y= 10

y=a(x+6)^2 +10 in vertex form

plug in the y intercept (0,-3) to solve for "a" the leading coefficient

-3 = a(0+6)^2 +10

36a = -13

a = -13/36

y = (-13/36)(x+6)^2 + 10