Tom K. answered 03/16/21
Knowledgeable and Friendly Math and Statistics Tutor
Let the speed of the boat in still water be s. Then, if the speed of the current is c, the speed of the boat is s - c upstream and s + c downstream.
c = 3
Thus, the time to go 3 km upstream is 3/(s - 3), and the time to go 4 km downstream is 4/(s + 3)
We are given that it takes twice as long to go upstream, so
3/(s - 3) = 2(4/(s+3))
Cross-multipling, we get, 8s - 24 = 3s + 9
5s = 33
s = 33/5
Then, to get 10 km upstream, it will take 10/(33/5 - 3) = 10/(18/5) = 50/18 = 2 7/9 hr
Ariel G.
thank you so much I got the same answer!03/16/21