Yefim S. answered 03/12/21
Math Tutor with Experience
1/5 + (1/5)2 + (1/5)3 + ... = ∑1∞(1/5)n = (1/5)/(1 - 1/5) = (1/5)/(4/5) = 1/4
We use formula for sum of infinite Geometric seciense: S∞ = a1/(1 - r)
Anya P.
asked 03/12/211/5 + (1/5)^2 + (1/5)^3 + ... =
Yefim S. answered 03/12/21
Math Tutor with Experience
1/5 + (1/5)2 + (1/5)3 + ... = ∑1∞(1/5)n = (1/5)/(1 - 1/5) = (1/5)/(4/5) = 1/4
We use formula for sum of infinite Geometric seciense: S∞ = a1/(1 - r)
∑(1/5)k where the index k runs from 1 to ∞.
This is a geometric series and the sum is (1/5)/(4/5) = 1/4
The sum of an infinite geometric series is a/(1-r) where a is the first term and r is the ratio.
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