An 1,427-bps digital signal is encoded first using 8B/10B and then transmitted using the MLT-3 baseband system, What bandwidth (in Hertz) is required for this transmission?

Question

An 1,427-bps digital signal is encoded first using 8B/10B and then transmitted using the MLT-3 baseband system, What bandwidth (in Hertz) is required for this transmission? 

Answer 1

For the 10/8 encoding,

In order to gain a data rate of 1 Gbps the line speed has to be

10/8 * 1 = 5/4*1 = 1.25 Gbps

100 Mb/s can be obtained out of 31.25 mhz

100 b/s = 31.25 hertz

100 b/s 1427

--------- = ------------

31.25 hz ?

100 * ? = 1427 * 31.25

? = 1427 * 31.25/100 = 446 hZ

Therefore 446 * 1.25 = 558