
Mark M. answered 03/06/21
Mathematics Teacher - NCLB Highly Qualified
1000 = 500e9k
2 = e9k
ln 2 = 9k
0.6931 ≈ 9k
0.0770 ≈ k
10000 = 1000e0.0770t
10 = e0.0770t
ln 10 = 0.0770t
2.3026 ≈ 0.0770t
29.9 ≈ t
In another 30 months they can fish.

Zack J.
asked 03/06/21Assume a population of fish grows exponentially. A pond is stocked initially with 500 fish. After 9 months, there are 1,000 fish in the pond. The owner will allow his friends and neighbors to fish on his pond after the fish population reaches 10,000. After how many months will the owner’s friends be allowed to fish?
Mark M. answered 03/06/21
Mathematics Teacher - NCLB Highly Qualified
1000 = 500e9k
2 = e9k
ln 2 = 9k
0.6931 ≈ 9k
0.0770 ≈ k
10000 = 1000e0.0770t
10 = e0.0770t
ln 10 = 0.0770t
2.3026 ≈ 0.0770t
29.9 ≈ t
In another 30 months they can fish.
John D. answered 03/06/21
Math tutor - many years experience university, high and grade school
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John D.
03/07/21