Factor the following expression:

Question

y³+10-24y³

Answer 1

y^3(1-24) + 10

= -23y^3 + 10

if you want you could factor out -23 and get a 2nd factor that's the sum of cubes

= -23(y^3 - 10/23)

You could use the sum or difference of 2 cubes formula to factor it further, but that's probably not what the problem was intended for

a^3 + b^3 = (a+b)(a^2+ab+b^2) substitute y for a and -cube root of 10/23 for b