Pre- calculus question

Question

Solve for x: 3^2x-3= 4√3

Answer 1

Take the log of both sides

log(3^2x-3)= log(4√3) The exponent moves to the front due to the power rule

(2x-3)(log 3) = log (4√3) Divine both sides by log 3

2x-3= log (4√3)/(log 3) Add 3 to both sides

2x= log (4√3)/(log 3) +3 Divide both sides by 2

x = [log (4√3)/(log 3) +3]/2 Then do all steps on the calculator

x=2.3809